The position of a particle is given by r = 3.0ti^+2.0t^2j^+5.0k^ when 't' is in seconds and 'r' to be in meter.
a) Find v(t) & a(t) of the particle.
b) Find v(t) & t = 1.0sec
Hello Kalpitha.., dr/dt = v = 3.0 i^ + 4.0 t j^
And value of v when t = 1 is given as 3 i^ + 4 j^
Hence mod is √32 + 42 = √25 = 5 m/s
Differentiating once again we get acceleration
a = 4.0 j^
And value of v when t = 1 is given as 3 i^ + 4 j^
Hence mod is √32 + 42 = √25 = 5 m/s
Differentiating once again we get acceleration
a = 4.0 j^