The probaility of selecting a red ball at random from a jar that contains only red,blue and orange ball is 1/4.The probability of selecting a blue ball at random from the same jar is 1/3.If this jar contains 10 orange balls,then what is the total number of balls in the jar?

let total no of balls be x
then - no. of red balls = x*[1/4]
   no. of blue balls = x*[1/3]
 no . of orange balls = 10   [given]
so    x = x[1/4] +x[1/3] + 10
         = x/4 + x/3 +10
          =[3x + 4x]/12 +10
         = 7x / 12 +10
        x  =[7x + 120]12
         [12]  x = 7x +120
12x = 7x + 120
12x -7x =120
5x =120 
x =120/5
x =24
so total balls =24
 
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@ Adarsh is correct.
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Thank u so much Adarsh:)
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thankssss
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probability of red ball ( 1/4) 

probability of blue ball ( 1/3 )

total orange balls = 10

now 

probability of orange ball = 1 - ( 1/4 ) - ( 1/3 )   [ all the probabilities sum up to 1 ]

let total balls be x 

 1 - ( 1/4 ) - ( 1/3 ) = [ 12 - 3 - 4 ] / 12 

= 5 / 12 

5x/12 = 10 [ probablity of orange ball is no of orange balls / total balls ]

=> x = 12*10 / 5 = 24 ....

hope this was simpler :)

 
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Thanks adarsh@@
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Thanks.
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I have also got the same....
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Your Intelligence is my common sense
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thank u
 
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Thanku
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the probability of selecting a red ball at random from a jar that contains onlyred, and orange balls is 1/4.the probability of selecting a ball at random from the jar is 1/3 .if the jar contains 10 orange balls, find the total number of balls in the jar
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Ans:24
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same as adarsh
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The solution was very much helpful. But I have a doubt, In case the probability is given is for withdrawing more than one ball. How should we proceed in such cases.
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What are you looking for?