the radius of a sphere is measured with an error?3% . What would be the error in surface area of the sphere?

Dear Student,Let r be the radius of the sphere.Given,Δrr×100=3%The surface area of the sphere is,A=4πr24π is a constant.Hence percntage error in surface area is,ΔAA×100=2×Δrr×100=2×3%=6%Regards.

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