# The radius of earth is 6.37 x 10^6 and its mass is 5.975 x 10^24 kg find the average density to appropriate significant figure

$Density=\frac{Mass}{Volume}\phantom{\rule{0ex}{0ex}}Volume=4/3\pi {r}^{3}=\frac{4}{3}\times 3.14\times (6.37\times {10}^{6}{)}^{3}=1082.14{m}^{3}\phantom{\rule{0ex}{0ex}}Mass=5.975\times {10}^{24}Kg\phantom{\rule{0ex}{0ex}}Density=mass/volume=5.52\times {10}^{21}Kg{m}^{-3}\phantom{\rule{0ex}{0ex}}Hopethisinformationwillclearyourdoubtsabouttopic.\phantom{\rule{0ex}{0ex}}Ifyouhaveanymoredoubtsjustaskhereontheforumandourexpertswilltrytohelpyououtassoonaspossible.\phantom{\rule{0ex}{0ex}}Regards$

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