The rate of diffusion of ozonised oxygen is 0.98 times that of pure Oxygen. The % by volume of ozone in the ozonised sample is

 Dear student

The Rate of diffussion of ozonised gas is slower than O2, it must have a higher molar mass. 

Diffusion rates are inversely proportional to the square root of the molar masses.

Therefore,

Molecular weight of ozonised gas = 32 g / (0.982) = 33.32 g

 Mixture of O2 with a molar mass of 32 g/mole and ozone with a molar mass of 48 g/mole 

Let Y be the mole fraction that is O2.

The mole fraction that is ozone = 1 - Y

Y x 32 g + (1 - Y) x 48 g/mole = 33.32 g/mole 

Y = 14.68 / 16

(1 - 14.68 / 16 ) x 100

= 8% O3 in the mixture

Hope this information will clear your doubts about topic.

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