the rates of diffusion of 2 gases are in the ratio 1:4. if the ratio of their masses present in the mixture effused is 2:3, calculate the ratio of their mole fraction.
please explain briefly!!!
We have,
So putting the values we get ,
= 1/4
So, M2 /M1 = 1/ 16
Now we have weight ratio of the gases : W1 /W2 = 2/3
So, mole fraction of gase 1, x1 = n1/n1+n2 and x2 = n2/n1+n2
Now , n1 =W1 /M1 , and n2 =W2 /M2 ,
So, putting the values and solving we get,
x1/x1= W1 x M2 /W2 x M1 =2 x 1/ 3 x 16 = 2/48 = 1/24
So ratio of mole fractions x1: x1= 1:24
I hope it is clear now!