the ratio of orbit and orbital angular momentum for 3d electron is a) √(2/3) b) √(3/2) c)√(3/1) d) √(1/3)

Question

​the ratio of orbit and orbital angular momentum for 3d
electron is a) √(2/3) b) √(3/2) c)√(3/1) d)
√(1/3)

Vartika Jain · Accepted Answer

Dear Student,

Orbital angular momentum =l(l+1)h2πFor d orbital, l=2Therefore, orbital angular molentum =2(2+1)h2π=6h2πorbit angular momentum= nh2πfor 3d, n=3orbit angular momentum= 3h2πorbit angular momentumOrbital angular momentum=3h2π6h2π=36=3332=32Hence, correct answer is (b)

​the ratio of orbit and orbital angular momentum for 3d electron is a) √(2/3) b) √(3/2) c)√(3/1) d) √(1/3)