The reaction 2N2O5 → 4NO2 + O2 takes place in closed container If the concentration of NO2 increases by - Chemistry - Chemical Kinetics

Question

The reaction 2N2O5 → 4NO2
+ O2 takes place in closed container If the
concentration of NO2 increases by 1 6 x 10-2
mol/lt in 4 sec,calculate the rate of the reaction and the rate of
change of concentration of N2O5

Monika Malik · Accepted Answer

Reaction is
2N2O5 → 4NO2 +
O2
Rate = 14(∆[NO2]∆t)
Rate = 14×(1
6 × 10-2 mol L-1 - 0)4 s
Rate = 1 0× 10-3 mol L-1
sâ€‹-1
Thus, the rate of reaction is 1 0× 10-3 mol
L-1 sâ€‹-1

Now, rate of change of concentration of
N2O5
Rate = -12( ∆[N2O5]∆t)
1 0× 10-3 mol L-1
sâ€‹-1 =
-12(∆[N2O5]∆t)
-(∆[N2O5]∆t) = 2 × 1 0× 10-3 mol
L-1 sâ€‹-1
-(∆[N2O5]∆t) = 2 0× 10-3 mol
L-1 sâ€‹-1

The reaction 2N2O5 → 4NO2 + O2 takes place in closed container. If the concentration of NO2 increases by 1.6 x 10-2 mol/lt in 4 sec,calculate the rate of the reaction and the rate of change of concentration of N2O5.

The reaction 2N₂O₅ → 4NO₂+ O₂ takes place in closed container. If the concentration of NO₂increases by 1.6 x 10^-2 mol/lt in 4 sec,calculate the rate of the reaction and the rate of change of concentration of N₂O_5.