The resistance of a wire at 300K is found to be 0.3ohms. If the temperature coefficient of resistance of wire is 1.5 *10^-3 per kelvin, the temperature at which the resistance becomes 0.6 ohms is (a)345K (b)993K (c)690K (d)720K Share with your friends Share 0 Decoder_2 answered this Dear student,R=Ro(1+αt)0.3=Ro(1+1.5×10-3×300)..........(1)case 20.6=Ro(1+1.5×10-3×T)........(2)Dividing eqn 1 by 2 we get0.60.3=(1+1.5×10-3×T)(1+1.5×10-3×300) 2×(1+1.5×10-3×300)=(1+1.5×10-3×T)2+900×10-3=(1+1.5×10-3×T)T=1.91.5×10-3=1266K or 993oCRegards 6 View Full Answer
