The right angled triangle ABC has a hypotenuse AC = 7 cm and side BC = 3 cm. Calculate the length AB and hence the angle ACB.
 

Dear student

In right angled  ABC, by pythagoras theorem H2=P2+B2   where H=hypotenuse,B=base,P=PerpendicularSo, AC2=AB2+BC2Given AC=7cm, BC=3 cm72=AB2+3249-9=AB2AB2=40So, AB=210 cmTo find: ACB  we need the concepts of trigo which will be taught in class10 but still providing the solution.sinθ=PH=ABAC=2107So, θ=sin-12107
Regards

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in right triangle ABC
(AC)2=(AB)2+(BC)
72=(AB)2+32
49-9=(AB)2
40=AB2
AB=2root10


 
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