The right triangle PQR , right - angled at Q as shown in the figure . What is the length of PR ?

Dear Student,

In PQRPQR = 90° GivenQSPR From vertex Q to hypotenuse PRQS2 = PS×SR        ....1Now, in PSQ, we have QS2 = PQ2-PS2 By Pythagoras theorem         = 42-x2         = 16-x2 cm        ....2From 1, we get QS2 = xx+4         = x2+4x            ....316-x2 = x2+4x2x2+4x-16 = 0x2+2x-8= 0 x2+4x-2x-8 = 0xx+4-2x+4 = 0x+4x-2 = 0x = -4,2Since length of side can't be negativeSo, x = 2 cmHence, PS=2 cm, SR = 6 cmPR = PS + SRPR = 2+6 = 8 cm

Regards

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