The same quantity of electricity is passed through 0.1 M H2SO4 and 0.1 M HCl . The amount of H2 obtained at the cathode are in ratio

Dear Student,

‚ÄčAccording to Faraday's second lawW1W2=E1E2Here, in both cases H2 is liberated at cathode. So, (Mass of H)HCl(Mass of H)H2SO4=Equivalent mass of HEquivalent mass of Hor, (Mass of H)HCl(Mass of H)H2SO4=1:1

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