The same quantity of electricity is passed through 0.1 M H2SO4 and 0.1 M HCl . The amount of H2 obtained at the cathode are in ratio Share with your friends Share 1 Vartika Jain answered this Dear Student, According to Faraday's second lawW1W2=E1E2Here, in both cases H2 is liberated at cathode. So, (Mass of H)HCl(Mass of H)H2SO4=Equivalent mass of HEquivalent mass of Hor, (Mass of H)HCl(Mass of H)H2SO4=1:1 12 View Full Answer