The second term of an AP is (x-y) and the fifth term is (x+y) then its first term is
according to the nth term formula,a+d=x-y and a+4d=x+y
let the equations be 1 and 2 respectively
therefore ,subtracting 2 from 1,we get -3d=-2y so d=2/3y
substituting value of d in equation 1,we get a+2/3y=x-y
therefore we can conclude that a=3x-5y/3
let the equations be 1 and 2 respectively
therefore ,subtracting 2 from 1,we get -3d=-2y so d=2/3y
substituting value of d in equation 1,we get a+2/3y=x-y
therefore we can conclude that a=3x-5y/3