THE SEMI PERIMETER OF A TRIANGLE IS 96cm. ITS SIDES ARE IN THE RATIO OF 3:4:5. FIND AREA OF THE TRIANGLE.

Hi Priyanka!
 
Let the sides a, b and c of the triangle be 3x, 4x and 5x respectively.
It is given that the semi-perimeter of the triangle is 96 cm.
 
∴ s = ½ of (a + b + c) = 96 cm
a + b + c = 2 × 96 cm = 192 cm.
⇒ 3x + 4x + 5x = 192 cm.
⇒ 12x = 192 cm.
x = 16 cm.
 
a = 3 × 16 cm = 48 cm, b = 4 × 16 cm = 64 cm and c = 45 × 16 cm = 80 cm.

Hope! This will help you.
Cheers!
 

  • 10

 semi peremeter = 96    s =  a + b+ c 2

let a = 3x, b = 4x and c = 5x

therefore, 3x + 4x + 5x 2 = 96

12x = 192

x = 16

a = 48 , b = 64 and c = 80 now you can easily find the answer.

                                                 

  • 0

What is c 2

  • -2

 Hi Priyanka!

 
Let the sides aand c of the triangle be 3x, 4and 5x respectively.
It is given that the semi-perimeter of the triangle is 96 cm.
 
∴ s = ½ of (a + b + c) = 96 cm
⇒ a + b + c = 2 × 96 cm = 192 cm.
⇒ 3x + 4x + 5= 192 cm.
⇒ 12x = 192 cm.
⇒ x = 16 cm.
 
∴ a = 3 × 16 cm = 48 cm, b = 4 × 16 cm = 64 cm and c = 45 × 16 cm = 80 cm.

 

 
 
  • 5

 hey priyanka hiiiiiiiiii,,,, in which skul u are??????

  • -2

hi i m in kv afs naliya

  • -1

sir r u from orissa?

  • -3
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