The shadow of a tower,standing on level ground,is found to be 45m longer when sun's altitude is 30^{0 }than when it was at 60^{0}.Find the height of the tower.

i need help

Dear Student!

Here is the answer to your query.

Let AB be the tower and AC and AD be its shadow when the sun's attitude is 60° and 30° respectively. Then, CD = 45 meters. Let h be the height of the tower and AC = *x* meters.

In ΔCAB, we have

In ΔDAB, we have

Substituting the value of *x* from equation (1) we get

Hence the height of the tower is 38.9 meters (approx)

Cheers!

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