The shadow of a tower,standing on level ground,is found to be 45m longer when sun's altitude is 300 than when it was at 600.Find the height of the tower.
i need help
Here is the answer to your query.
Let AB be the tower and AC and AD be its shadow when the sun's attitude is 60° and 30° respectively. Then, CD = 45 meters. Let h be the height of the tower and AC = x meters.
In ΔCAB, we have
In ΔDAB, we have
Substituting the value of x from equation (1) we get
Hence the height of the tower is 38.9 meters (approx)