# The shadow of a tower,standing on level ground,is found to be 45m longer when sun's altitude is 300 than when it was at 600.Find the height of the tower.i need help

Dear Student!

Let AB be the tower and AC and AD be its shadow when the sun's attitude is 60° and 30° respectively. Then, CD = 45 meters. Let h be the height of the tower and AC = x meters.

In ΔCAB, we have

In  ΔDAB, we have

Substituting the value of x from equation (1) we get

Hence the height of the tower is 38.9 meters (approx)

Cheers!

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