the side YZ of triangle XYZ is produced to a point L. the bisector of angle YXZ meets YZ at the point M. prove that angle XYZ+ angle XZL=2angle XMZ. PLZZ give me answer fast???

To Show : XYZ +XZL =2XMZWe know,exterior angle of a triangle is equal to the sum of two opposite interior angles.XZLis an exterior angle of XYZ.Thus,XZL=ZXY +XYZZXY=XZL -XYZ...(i)Also,XZLis an exterior angle of XMZ.Thus,XZL=ZXM +XMZXZL=ZXY2 +XMZ  (Since XM is angle bisector of ZXY)ZXY=2XZL-2XMZ...(ii)From (i) and (ii),we haXZL -XYZ=2XZL-2XMZ XYZ +XZL =2XMZ

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