The sides of a triangle are in the ratio of 25 14 12 and its perimeter is 510m. The greatest side of the triangle is
given,
sides are in ratio of 25:14:12
perimeter = 510 m
let, sides be = 25x , 14x , 12x
.
. . a + b + c = perimeter
25x + 14x+ 12x = 510
51x = 510
x = 510/51 = 10
1st side = 25 x 10 = 250m
2nd side = 14 x 10 =140m
3rd side = 12 x 10 = 120m
.
. . The greatest side is the first side i.e.250m
sides are in ratio of 25:14:12
perimeter = 510 m
let, sides be = 25x , 14x , 12x
.
. . a + b + c = perimeter
25x + 14x+ 12x = 510
51x = 510
x = 510/51 = 10
1st side = 25 x 10 = 250m
2nd side = 14 x 10 =140m
3rd side = 12 x 10 = 120m
.
. . The greatest side is the first side i.e.250m