The sides of a triangle are in the ratio of 25 14 12 and its perimeter is 510m. The greatest side of the triangle is

given,
sides are in ratio of 25:14:12
perimeter = 510 m
let, sides be = 25x , 14x , 12x
​  .
.  .  a + b + c = perimeter
   25x + 14x+ 12x = 510
             51x          = 510
                       x    = 510/51  = 10

    1st side = 25 x 10 = 250m
    2nd side = 14 x 10 =140m
   3rd side = 12 x 10 = 120m
 .
.  . The greatest side is the first side i.e.250m
                               
  • 4
given,
sides are in ratio of 25:14:12
perimeter = 510 m
let, sides be = 25x , 14x , 12x
​  .
.  .  a + b + c = perimeter
   25x + 14x+ 12x = 510
             51x          = 510
                       x    = 510/51  = 10

    1st side = 25 x 10 = 250m
    2nd side = 14 x 10 =140m
   3rd side = 12 x 10 = 120m
 .
.  . The greatest side is the first side i.e.250m
  • 1
given,
sides are in ratio of 25:14:12
perimeter = 510 m
let, sides be = 25x , 14x , 12x
​  .
.  .  a + b + c = perimeter
   25x + 14x+ 12x = 510
             51x          = 510
                       x    = 510/51  = 10

    1st side = 25 x 10 = 250m
    2nd side = 14 x 10 =140m
   3rd side = 12 x 10 = 120m
 .
.  . The greatest side is the first side i.e.250m

I hope its help you
  • 1
What are you looking for?