the slope of a common tangent to the ellipse x2/a2 + y2 /b2 =1 and a concentric circle of radius r is ( r2 -b2 )1/2/(a2-r2)

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Please find below the solution to the asked query:

We havex2a2+y2b2=1Line y=mx+c is tangent to this ellipse ifc2=a2m2+b2....iCentre of ellipse is 0,0 and as circle is concentric hence its centre will alsobe 0,0.Radius is r, hencex2+y2=r2Line y=mx+c is tangent to this circle ifc2=r21+m2....iiBy i and iia2m2+b2=r21+m2a2m2+b2=r2+r2m2a2m2-r2m2=r2-b2m2a2-r2=r2-b2m2=r2-b2a2-r2m=r2-b2a2-r2

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