The solubility of BaSO_4, in water, is 2.33 x 10^-3 gL^-1.Its solubility product will be?
a) 10^-15
b) 10^-10
c) 10^-5
d) 10^-20

well the answer is option (b)....but sorry i don't know the process...

Solubility is always is mol L-1 . To make 2.33*10-3 in mol L-1 we divide it by its molecular weight . S = 2.33*10-3/233 = 10-5 mol L-1 . Ksp of BaSO4 = s2 = 10-5*10-5 = 10-10 .

Solubility of BaSO4 =2.33 ×10^-3 S= 2.33×10^-3/233 =10^-5 S^2=(10^-5)^2 =10^-10

I hope this is the right answer