The solubility product of ferric hydroxide is 1.1 x 10^-36 at 298 K. Calculate the solubility of ferric hydroxide in gram per litre. Share with your friends Share 2 Yasodharan answered this Dear Student, The computation are expressed below, Fe(OH)3⇌Fe3++3 OH-Ksp=[Fe3+][OH-]31.1×10-36=(x)(x)3x=1×10-9 molLfor conversion molar mass is used,Fe3+=10-9 molL × 55.85 gmol=5.58×10-10 gLOH-=10-9 molL × 51 gmol = 5.4×10-10 gL Regards. -1 View Full Answer
