The solubility product of SrF2 in water is 8 x 10-10. Calculate its solubility in .01 M NaF aqueous solution. Share with your friends Share 2 Pratik Bharadia answered this A bit correction in the question --- it is 0.1 M NaF aq. solution. -6 View Full Answer Vidhi Bhati answered this Let the new solubility be S', so.. S' ( 2S'+ 0.1)^ 2= 8* 10^-10 2S' -2 Sidharat Kumar answered this Hg -7 Arpit Jain answered this Answer is given in this picture 20 Priya Jethwani answered this Answer is 8 * 10^-8........ HOPE IT WILL HELP YOU........ 2 Avinash Jha answered this Fiduciary -5 Akansha Ranjan answered this 8*10^-8 0 Arpita Tiwari answered this nicess 0
