The specific conductance of a saturated solution of AgCl at 25°C after subtracting the specific conductance of conductivity of water is 2.28 × 10^{–6 }mho cm^{–1}. Find the solubility product of AgCl at 25°C. $\left({\mathrm{\lambda}}_{\mathrm{AgCl}}^{\infty}=138.3\mathrm{mho}{\mathrm{cm}}^{2}\right)$