The specific conductivity of a 0 12 N solution of an electrolyte is 2 4 × 10^-2 S cm^-1 - Chemistry - Solutions

Question

The specific conductivity of a 0 12 N solution of an electrolyte is
2 4 × 10^-2 S cm^-1 Calculate its equivalent conductance

Shiv@m P · Answer

Equivalent conductivity=K*1000/N
K=conductivity
N=normality
=2 4*10^-2 *10^3/0 12

=24/0 12 =200

The specific conductivity of a 0.12 N solution of an electrolyte is 2.4 × 10^-2 S cm^-1. Calculate its equivalent conductance