The speed of a projectile at its maximum height is 6m/s . If it stays in the air for a total time of 8 sec its horizontsl range is
Dear student,
In horizontal direction, the projectile would move with its horizontal component of velocity v0 cosϴ = 6ms-1 in all its trip. The time it stays in space is 8 sec, thus horizontal range it would cover is 8 sec x 6ms-1 = 24 m.
Regards.
In horizontal direction, the projectile would move with its horizontal component of velocity v0 cosϴ = 6ms-1 in all its trip. The time it stays in space is 8 sec, thus horizontal range it would cover is 8 sec x 6ms-1 = 24 m.
Regards.