the standard emf of the cell, Cd(s) / CdCl2(aq)(0.1M) // AgCl(s) / Ag(s) in which reaction is 0.6195V at 0 degree Celsius and 0.6753V at 25 degree Celsius. the value of deltaH of the reaction at 25 degree Celsius is

1. The formula used is Gibbs Helmoltz equation :

       G=H-TS2. From the data in question: G1(273K) =-nFE=-2×96500×0.6195=11.96 kJ G2(298K) = -nFE=-2×96500×0.6753=13.03 kJ3. Using equation 1 :    11.6 kJ =    H-273S            ...(1)- 13.03 kJ =-H+298S          ...(2)we get,  S =-572 JK-1   H= 145.9 kJ         

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