the straight line y=m1x+c1,y=mx+c2,and x=0 intersect in the pointsP,Q and R.find the area of the triangle PQR..WHAT IS THE VALUE OF THE AREA IF C1=C2?

pt of intersection of ---   (Solving each equations simultaneously)

1. y=m1x+c1 and y= m2x+c2 is P( x= (c2-c1) / (m1+m2)  y= (m1c2 +m2c1 ) / (m1+m2)  )  == (x1,y1)

2. y=m1x+c1 and x=0 is Q(0,c1) == (x2,y2)

3. y=m1x+c2 and x=0 is R(0,c2)  == (x3,y3)

Area of the traingle formed by three points is | x1(y2-y3) + x2(y3-y1) + x3(y1-y2) | / 2    ( Vertical Line '|' denotes                                                                                                                                       modulus function )

Substituting the respective values  we get , { | (c2-c1) (c1-c2) / (m1+m2) | }  / 2

      => (c2-c1)² / (m1+m2)   ........... (c1-c2) becomes -(c2-c1) After applying modulus we get (c2-c1)