# The sum of the angles of a polygon is 8100deg how many sides does it have

Please find below the solution to the asked query:

Given : Sum of all interior angles of a polygon = 8100$\xb0$

We know " If any polygon have '

*n*' sides then sum of interior angle is = (

*n*- 2 ) $\times $ 180$\xb0$ " .

So,

(

*n*- 2 ) $\times $ 180$\xb0$ = 8100$\xb0$ , Now we divide by 180$\xb0$ both hand side and get

(

*n*- 2 ) = 45 ,

*n*- 2 = 45

*n*= 47

Therefore,

**Given polygon have total number of sides = 47 ( Ans )**

Hope this information will clear your doubts about topic.

If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.

Regards

**
**