the sum of the digits of a two-digit number is 11 the number got by interchanging the digits is 27 more than the original number what is this number Share with your friends Share 0 Lovina Kansal answered this Dear student Let the digit at one's palce is x and the digit at ten's place is yThen originla number=10y+xSum of digits=x+y=11 ...(1)And Acc to question,we have10x+y=27+10y+x⇒9x-9y=27⇒x-y=3 ....(2)Adding (1) and (2), we get2x=14⇒x=7Put the value of x in (1), we get7+y=11⇒y=4So, the original number=10(4)+7=47 Regards -1 View Full Answer Bishakha Bhattacharjee answered this Let the digit in unit place be X. and the digit in ten's pace be (11 - X) Therefore, the number is = 10(11 - X) + X = 110 - 10x + x = 110 - 9x And the reversed number is =10X + (11 - x) = 10x + 11 - x = 9x + 11 now, according to question, 110 - 9x + 27 = 9x + 11 => 137 - 9x = 9x + 11 => 137 - 11 = 9x + 9x => 18x = 126 => x = 126/18 => x = 7 therefore, the number is = 110 - 9x = 110 - 9 * 7 = 110 - 63 = 47 2
