the sum of the first n terms of an AP whose first term is 8 and difference is 20 is equal to sum of 2n terms of another AP whose first term is -30 and common difference is 9. Find the AP

Given, sum of the first n terms of an AP whose first term is 8 and difference is 20 is equal to the sum of 2n terms of another AP whose first term is -30 and common difference is 9.

 So, according to the given condition,

Here, the value of n is coming in decimal which can't be possible. So, please recheck your query.

Moreover, your series for the first a.p will be:

8,  8 + 20,  8 + 20 + 20, ........

= 8, 28, 48, .......  

  • -13

 AP= 8, 28, 48, 68, ............

  • -5

 can u explain

  • -6

 First term(a)= 8 and common difference(d)= 20.

AP= a, a+d, a+2d .........

     =8, 8+20,8+40 .........

     =8, 28, 48, ..............

  • -4
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