the sum of the rational terms in the binomial expansion of (2^1/2 + 3^1/5)^10 ?? Share with your friends Share 3 Priyanka Kedia answered this Given binomial expansion is, 212+31510So,Tr+1=Cr1021210-r315r, Where r=0,1,2,....10For rational term,r=multiple of 5=0,5,10 ......110-r=multiple of 2=0,2,4,6,8,10 ......2From equation 1 and 2, the possible values of r is 0 and 10. Thus, sum of rational terms=T0+1+T10+1 =C01021210-03150+C101021210-1031510 =1×25×1+1×1×32 =32+9 =41Hence, sum of rational terms in given binomial expansion is 41. 30 View Full Answer