the sum of three consecutive multiples of 9 is 999 find these multiples
let the first no. to be x
other no. are x + 9 and x + 18
so their sum will be = 999
x + x +9 + x + 18 = 999
3x + 27 = 999
3x = 999 - 27
3x = 972
x = 972 /3
x = 324
first no . is 324
another one is 324 + 9= 333
last no. is 324 + 18 = 342
so 324 ,, 333 ,, 342 are the three consecutive multiples of nine which add upto 999
other no. are x + 9 and x + 18
so their sum will be = 999
x + x +9 + x + 18 = 999
3x + 27 = 999
3x = 999 - 27
3x = 972
x = 972 /3
x = 324
first no . is 324
another one is 324 + 9= 333
last no. is 324 + 18 = 342
so 324 ,, 333 ,, 342 are the three consecutive multiples of nine which add upto 999