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the sum of three numbers in A.P. is 33 and the sum of their cubes is 5409. find the numbers?

Let the numbers are.

Given that the sum of three numbers in AP is 33 and sum of their cubes is 5409. So,

And,

Substitute value of in above equation,

So,

Hence numbers are 7, 11, and 15.

 

Note: The question is wrong. sum of their cubes will 5049 instead of 5409.

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no.s in A.p = a-d,a,a+d

atq

a-d+a+d+a=33

therefore

3a=33

a=11

now put  the value of a in eqn

(a+d)cube+a cube+(a-d)cube

u will gt the answer that is value of d

thn put the values of a and d in 1.a-d

2.a

3.a-d  they will be the 3 no.s that is ur answer

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