The sum of two numbers is equal to nine times their difference.If the larger number is more than the smaller by 33,what is their sum

Let the smaller no. is  x
  therefore-   larger no. = x+33

their sum=  x+x+33 
their differense =  x-(x+33)

ATQ(according to the question) - 

          x+x+33 =  9[x-(x+33)]
      =>2x+33  =   9[x-x-33]
      =>2x+33  =   9* (-33)
      =>2x        =  -297 - 33
      =>2x        =    -    330
      =>     x     =     -330 /  2  
      =>     x     =    -165

therefore , 
                  smaller no. =   -165  
                  larger no.  =   -165+33 =  -   132

So,
            their sum =  -165+(-132)
                            =    - 297                                             Ans....