The temperature at which the speed of sound in air becomes double of its value at 27 degee celsius?
(a)= -123 deg cel
(b)= 927 deg cel
(c)= 327 deg cel
(d)= 54 deg cel
Use the formula
velocity of sound waves v = sqrt (P/rho)
P is the pressure and rho is the density.Write this as
v1 = root(p1/rho)
v2= root (p2/rho)
square both sides
v1^2 = p1 /rho
v2^2 = p2/rho
Take the ration
v1^2/v2^2 = p1/p2
Put the values v1=1 and v2 = 2
YOu get
1/4 = p1/p2
p1 = n kb T1 and p2= n kb T2. Here n is the number density. kb Boltzmann constant and T1 and T2 are temperatures.
If you use it in the above equation you get
T2= 4 T1
T1 is 27 degrees= 273 + 27 = 300
T2= 1200 degrees = 1200-273 = 927 degrees.
velocity of sound waves v = sqrt (P/rho)
P is the pressure and rho is the density.Write this as
v1 = root(p1/rho)
v2= root (p2/rho)
square both sides
v1^2 = p1 /rho
v2^2 = p2/rho
Take the ration
v1^2/v2^2 = p1/p2
Put the values v1=1 and v2 = 2
YOu get
1/4 = p1/p2
p1 = n kb T1 and p2= n kb T2. Here n is the number density. kb Boltzmann constant and T1 and T2 are temperatures.
If you use it in the above equation you get
T2= 4 T1
T1 is 27 degrees= 273 + 27 = 300
T2= 1200 degrees = 1200-273 = 927 degrees.
