The temperature inside a refrigerator is t2°C and the room temperature is t1°C. The amount of heat delivered to the room for each joule of electrical energy consumed ideally will be: (1) t 2 + 273 t 1 - t 2 (2) t 1 + t 2 t 1 + 273 (3) t 1 t 1 - t 2 (4) t 1 + 273 t 1 - t 2 Share with your friends Share 2 Pintu B. answered this Dear Student , Coefficient of performance (COP) of a refrigerator ,β=Q2Q1-Q2Therefore ,COPβ=Q2Q1-Q2=T2T1-T2=t1+273t1+273-t2-273=t1+273t1-t2 Regards -17 View Full Answer