The third term of a GP is 4 , find the product of its first five terms .

( answer = 1024 )

let the terms be a /r^2 , a/r , a ,ar, ar^2

now product =  a/r^2 * a/r * a* ar* ar^2

  = a^5

  = 4 ^5

  = 1024

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A3 =4 = ar2

product of first five terms ....

a(ar)(ar2 )(ar3 )(ar4 )= a5 r10

= (ar2)5

= (4)5

=1024

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Karan Muvval is ​absolutely right.
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Please find this answer

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Please find this answer

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Answer of your question;--

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Karan muval is absolutely right
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1024
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1024
 
  • 0
1024
 
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halooo
your answer is 1024
 
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Hope this helps.........
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1024
 
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Let the GP be a , ar , ar2 , ar3 ....
T3 = ar=4
We need to find product of first five tems, so
T1 * T2 * T3 * T4 * T5 = a * ar * ar2 * ar3 * ar4
                                    
    =a5r10
                                         
=(ar2)5
                                  =(4)5
                                  = 1024
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Pls. find your answer below in image
your answer's solution
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Pls find below

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1024
 
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Please find this answer

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A3=4=ar^2 a(ar)(ar^2)(ar^3)(ar^4) Product of first 5 terms are a^5r^10= (ar^2)^5 = 4^5 Done. OK love u will u be my girlfriend 8421023221
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LET THE FIVE TERMS BE  a / r 2 , a / r , a , a r , a r 2 ;
THIRD TERM IS 4 (i.e) a = 4;
a / r* a / r * a * a r * a r 2 = a5 = 4 5 =1024
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If seventh term like between 130 and 140. Find common diff
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Ahiy uip
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Answer

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a straight line passes through two three and the portion of the line intercepted between the axis is bisected at this point find its equation
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1024 is the answer

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Find the some of the Gp

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A3=4=ar2
product of first five terms
a.ar.ar2.ar3.ar4= a5r10
                     = (ar2)5
                     = 45
                     =1024
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