The time taken by the galvanic cell which operates almost ideally under reversible conditions at a current of 10 16 - Chemistry - Atoms and Molecules

Question

The time taken by the galvanic cell which operates almost ideally
under reversible conditions at a current of 10–16
A to deliver 1 mole of electron is
(1) 19 30 × 1020 S (2) 4 825 ×
1020 S
(3) 9 65 × 1020 S (4) 3 4 × 1011
S

Ashwini Kumar Mishra · Accepted Answer

Dear student ,
1 mole of electron requires 1F (96500 C ) of electricity
therefore from Q = i t we have 96500 = 10-16 ×
t
there fore t = 9 65 × 1020 sec (option 3 )
Regards

The time taken by the galvanic cell which operates almost ideally under reversible conditions at a current of 10–16 A to deliver 1 mole of electron is (1) 19.30 × 1020 S (2) 4.825 × 1020 S (3) 9.65 × 1020 S (4) 3.4 × 1011 S

The time taken by the galvanic cell which operates almost ideally under reversible conditions at a current of 10^–16A to deliver 1 mole of electron is
(1) 19.30 × 10²⁰ S (2) 4.825 × 10²⁰ S
(3) 9.65 × 10²⁰ S (4) 3.4 × 10¹¹ S