the total no. of valence electrons in 4.2g of N3- ion is ??in terms of Na(Na is the avogadro no._)

Number of moles of nitride ions in 4.2 g = 4.2/14

  = 0.3 moles

Therefore, number of nitride ions in 0.3 moles = 0.3 x Na

Number of valence electrons in one nitride ion = 8

So, number of valence electrons in 0.3 x Na nitride ions = 8 x 0.3 x Na

  = 2.4 x Na

  • -69

i n3 ion=10 elctrons]

1g=1mole=6.o22*1023

4.2*6.022*1023*10

  • -66
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