The treatment of alkyl chlorides with aqueous KOH leads to the formation of alcohols but in the presence of alcoholic KOH, alkenes are major products. Explain.

Alkyl chloride in the presence of aqueous KOH gives substitution product i.e. alcohol. However, alkyl chloride containing β-hydrogen atom with alcoholic KOH solution, undergo elimination reaction to give alkene as major product.

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This is becaues Alcoholic KOH + Alkene = Dehydrohalogenation Reaction (Removes HX), thus forming aa Alkene with a double bond. Aqueous KOHleads to the formation of Alcohol.

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