the trunk of a tree cracks at a point 10m above the ground the tree falls and its top touches the ground at the distance of 24m from the base of the tree find the actual height of the tree
we can find by the pythagoreas theroem = a2 + b2 = c2
= 10 2 + 242 = c2
676 = c2
c = square root of 676
so c = 26 m
so actual height of tree = 10 m + 26 m = 36 m
= 10 2 + 242 = c2
676 = c2
c = square root of 676
so c = 26 m
so actual height of tree = 10 m + 26 m = 36 m