the unit cell of an element of atomic mass is 96 and density 10.3g/cm3. edge length of 314pm. find the structure of crystal lattice.
Using the Formula,
d = 10.3 g/cm3
a = 314 pm = 3.14 x 10-8 cm
M = 96 g/mol
NA = 6.022 x 1023
So,
z = 10.3 x ( 3.14 x 10-8)3 x 6.022 x 1023 /96
= 2
So, the lattice will be Bcc i.e. Body centered Cubic.