the unit cell of an element of atomic mass is 96 and density 10.3g/cm3. edge length of 314pm. find the structure of crystal lattice.

Using the Formula,

d = 10.3 g/cm3

a = 314 pm = 3.14 x 10-8 cm

M = 96 g/mol

NA = 6.022 x 1023

So,

z = 10.3 x ( 3.14 x 10-8)3 x 6.022 x 1023 /96

 =  2 

So, the lattice will be Bcc i.e. Body centered Cubic. 

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