the units digit of a two -digit number is 3 and seven times the sum of the digits is the number itself.Find the number .

Unit digit of a two digit no = 3

Let digit at tens place be x

Two digit No. = 10 * tens place + 1 * ones place

  = 10x+3

7(x + 3) =10x + 3

7x + 21 = 10x+3

21-3 = 10x-7x

x=18/3

x=6

Two digit no = 10*6+3

  =  60+3

  = 63

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It's 63
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