The V-I graph of a metallic wire at two temperatures T 1 and T 2 where slope of T 2 is greater than slope of T1
Which of the twotemperatures is higher and why?
We know that for conductors the resistance increases with temperature.
Now, the slope of a typical V-I graph for a conductor represents the resistance or
R = V/I = slope
now, as the slope of metal 2 is greater than metal 1 then the resistance of metal 2 will also be grater than metal. This would mean that temperature (which is directly related to resistance) will be greater for metal 2 compared to metal 1.
The T1 slope will have higher temperature.
THEN if the I is greater then the resistance will also be greater
R the resistance is directly proportional to temperature by the principle of collison of the electron
now in this graph T1 has mor bent towards I so more current
HENCE T1 has more temperature.