The Value of arg(z)+arg(z conjugate) = ?

let arg(z) be x

then arg(z conjugate) = -x

arg(z) + arg(z conjugate) = x+-x = 0

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Argz+Arg(conjugatez)
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Hey !

Let Z = a + ib

=> Arg Z = Tan^-1 b / a

=> Arg Z ( Conjugate ) = Tan^-1 - b / a 

=> Arg Z + Arg Z ( conjugate ) = b / a - b / a = Tan^-1 ( 0 ) = 0

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See this pic.. And get relaxed 😊

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