The value of delta H' in kJ for the reaction will be CS2 (l) + 4NOCl(g) = CCl4(l) + 2N2 - Science - Atoms and Molecules

Question

The value of delta H' in kJ for the reaction will be CS2 (l) +
4NOCl(g) = CCl4(l) + 2N2 (g) if Hf (CS2) = -x , Hf (NOCl) = -y,
Hf(CCl4)= +z, Hf (SO2)= -r ?

Shivani Parihar · Answer

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The value of delta H' in kJ for the reaction will be CS2 (l) + 4NOCl(g) = CCl4(l) + 2N2 (g) if Hf (CS2) = -x , Hf (NOCl) = -y, Hf(CCl4)= +z, Hf (SO2)= -r ?