the value of Kc = 4 24 at 800K for the reaction CO(g) + H2O(g) CO2(g) + H2(g) Calculate the - Chemistry - Equilibrium

Question

the value of Kc = 4 24 at 800K for the reaction
CO(g) + H2O(g) CO2(g) + H2(g)
Calculate the equilibrium concentration of CO2 ,H2O ,CO , H2 at
800K ,if only CO and H2O are pesent initially at concentration of 0
10M each

Kumar Sarang · Accepted Answer

For the reaction,

CO (g) + H2O (g) â‡” CO2
(g) + H2 (g)

Initial
concentration:

0 1M
0 1 M
0
0

Let x mole per litre of each of the productbe
formed

At equilibrium:

0 1 - x M
0 1 - x M
x M
x M

where x is the amount of CO2 and H2 at
equilibrium

Hence, equilibrium constant can be written
as,

Kc= x2/(0
1-x)2 = 4 24

x2 = 4 24(0 01 + x2-0
2x)

x2 = 0 0424 + 4 24x2-0
848x

3 24x2 â€“ 0 848x
+ 0 0424 = 0

a = 3 24, b = â€“ 0 848, c =
0 0424

for quadratic equation ax2 + bx +
c = 0,

Thus solving we get two values of
x

x1= 0 067 x2= 0 194

Neglecting x2= 0 194 becuase x could not be more than
initial concentration

Hence the equilibrium concentrations
are,

[CO2] = [H2] = x = 0
067 M

[CO] = [H2O] = 0 1
â€“ 0 067 = 0 033 M

the value of Kc = 4.24 at 800K for the reaction CO(g) + H2O(g) CO2(g) + H2(g) Calculate the equilibrium concentration of CO2 ,H2O ,CO , H2 at 800K ,if only CO and H2O are pesent initially at concentration of 0.10M each.

the value of Kc = 4.24 at 800K for the reaction

CO(g) + H2O(g) CO2(g) + H2(g)

Calculate the equilibrium concentration of CO2 ,H2O ,CO , H2 at 800K ,if only CO and H2O are pesent initially at concentration of 0.10M each.