The value of spearman's rank correlation coefficent no of observations was found to be 2/3. The sum of the squares of differences between the corresponding ranks was 55. Find the no. of pairs.

Dear Student
As we know
rk = 1 - 6D2N3 - N
Where 
​​​​​​rk   = Coefficient of rank correlation
D = Rank differences
N = Number of pairs

Given - 
​​​​​​rk   = 2/3
ΣD2 = 55
N = ?


Regards
 

  • 0
What are you looking for?