the value of the det. of a matrix A of order 3x3 is 4. find the value of of |5A|

We know that If A is a square matrix of order n, thenkA = knAso, 5A = 53A = 125 × 4 = 500

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From The property of det. We know that if a given det is multiply by a constant K ,then the new det is K times the original det

Now,|A|=4

5|A|=5x4

=20

  • -3

the above mentioned solution by ropienglien is totally incorrect. here is the correct one

5A implies every element in the matrix will get multiply by 5 . now take 5 common from either each row or each column to give 5*5*5 |A| = 125|A| = 500

thumbs up^^^^^^^^

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