The vapour pressure of pure liquid X and pure liquid Y at 25°C are 120 mm Hg and 160 mm Hg respectively. If equal moles of x and y are mixed to form an ideal solution, calculate the vapour pressure of solution

Vapour pressure of solution = Ps = PX0ΧX+PY0ΧY
Since equal moles of X and Y are mixed, let mole fraction of X and Y be 0.5 each.
Putting the given values, we get
Ps = 1200.5+1600.5
Ps =
60 + 80 = 140 mm Hg

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