The vapour pressure of pure liquid X and pure liquid Y at 25 C are 120 mm Hg and 160 - Science -

Question

The vapour pressure of pure liquid X and pure liquid Y at 25°C
are 120 mm Hg and 160 mm Hg respectively If equal moles of x and y
are mixed to form an ideal solution, calculate the vapour pressure
of solution

Yatin Bhatia · Accepted Answer

Solution
Vapour pressure of solution = Ps =
PX0ΧX+PY0ΧY
Since equal moles of X and Y are mixed, let mole fraction of X and
Y be 0 5 each
Putting the given values, we get
Ps = 1200 5+1600 5
Ps = 60 + 80 = 140 mm Hg

The vapour pressure of pure liquid X and pure liquid Y at 25°C are 120 mm Hg and 160 mm Hg respectively. If equal moles of x and y are mixed to form an ideal solution, calculate the vapour pressure of solution