The vertical angle of an isosceles triangle is 2/3 each of its base angles. Find it in radians.

Dear student
each of the base angle has measure x.then x+x+23x=180°   [By angle sum property of triangle]3x+3x+2x3=180° 8x=540°x=67.5°x=67.5×π180cx=3π8 radians
Regards

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